14. 解决方案：练习题

** 这里是一种解法：**

** 问题：** 编写一个名为director_win的函数，它接受2个参数，winners字典和导演名称。它应该返回与导演相对应的奥斯卡奖的数量。

# function that takes the winners dictionary and the director name as arguments and returns win counts
def director_win(winners, director_name):
    win_count_dict = {}
    for year, winnerlist in winners.items():
        for winner in winnerlist:
            win_count_dict[winner] = win_count_dict.get(winner,0)+1
    if director_name in win_count_dict:
        return (win_count_dict[director_name])
    else:
        return 0